Is the a_0(1450) a candidate for the lowest q\bar{q} ^3P_0 state?

Abstract

For the $a_0(1450)$, considered as the $q\bar{q}{1}^3{P}_0$ state, "experimental" tensor splitting, $c_{exp}=(-150\pm 40$) MeV, appears to be in contradiction with conventional theory of fine structure. There is no such discrepancy if the $a_0(980)$ belongs to the $1^3{P}_{J}q\bar{q}$ multiplet. The hadronic shift of the $a_0(980)$ is shown to be strongly dependent on the value of the strong coupling in spin-dependent interaction.

Comments: 13 pages