PaperPanorama

Nuclear Theory·nucl-th

Tuesday·May 24, 2016

7 papers2 primary·5 cross-listed

  1. 01

    A possible framework of the Lipkin model obeying the su(n)-algebra in arbitrary fermion number. II --- Two subalgebras in the su(n)-Lipkin model and an approach to the construction of linearly independent basis ---

    Yasuhiko Tsue (Kochi Univ., Japan) · Constanca Providencia (Univ. de Coimbra, Portugal) · Joao da Providencia (Univ. de Coimbra, Portugal) · Masatoshi Yamamura (Kansai Univ., Japan)

    Standing on the results for the minimum weight states obtained in the previous paper (I), an idea how to construct the linearly independent basis is proposed for the su(n)-Lipkin model. This idea starts in setting up m independent su(2)-subalgebras in the cases with n=2m and n=2m+1 (m=2,3,4,...). The original representation is re-formed in terms of the spherical tensors for the su(n)-generators built under the su(2)-subalgebras. Through this re-formation, the su(m)-subalgebra can be found. For constructing the linearly independent basis, not only the su(2)-algebras but also the su(m)-subalgebra play a central role. Some concrete results in the cases with n=2, 3, 4 and 5 are presented.

    nucl-thPTEP(2016)·2 citations
  2. 02

    An octahedral deformation with six alpha particles at the Z = 12 system, Mg nuclides: Third nucleons, Alpharons

    Chang-Bum Moon

    We suggest that the emergence of a large deformation in the magnesium, Mg, nuclides, especially at the Z = 12, N = 12, should be associated with an octahedral deformed shape. Within the framework of molecular geometrical symmetry, we find a possibility that the Z = 12, N = 12 system would form an octahedral structure consisting of six points of alpha(4He) particles, yielding the ground collectivity. With this point of view, we draw the following serial molecular structures; the Z = 10, N = 10, 20Ne, corresponds to a hexahedral, the Z = 8, N = 8, 16O, does to a tetrahedral, and the Z = 6, N = 6, 12C, does to a trigonal symmetry. Moreover, the Z = 2, N = 2, 4He(alpha), fits into a tetrahedral symmetry with four points of nucleons; two protons and two neutrons. The enhanced deformation at Z = 12 with N > 20 would be explained by a deformed shape related to an Ethene(Ethylene)-like skeleton with six alpha particles. The deformation at Z = 10, with N = 10 and 12, can be interpreted as being attributed to a hexahedral shape combined by five alpha particles as well. By noticing that the Z = 4, N = 4 system is unstable to the ground state under two-body system with two alpha particles, we conclude that alpha particles, rather than the eight-protons-neutrons nucleon, govern the 8Be stability. Accordingly, the alpha particle should be a third nucleon, like a proton or a neutron, in a nucleus. We name it the 'Alpharon'. With this picture, we are able to open a new gate toward understanding of nuclear many-body systems; nucleon-nucleon interaction, shell structures, nucleon-synthesis, and nuclear matters. We argue that nature favors three-body systems; three quarks for a nucleon, three nucleons for a nucleus.

    nucl-thnucl-ex0 citations

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